If it's not what You are looking for type in the equation solver your own equation and let us solve it.
28u^2+15u=0
a = 28; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·28·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*28}=\frac{-30}{56} =-15/28 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*28}=\frac{0}{56} =0 $
| 2x+23-4x-29=90 | | 20x-19x=20 | | x+15+(2x)=180 | | -2b+8=6b | | 14+n=-1 | | 16=160/n | | 12(5+2y)=4y-(5-9y)72+24y=4y-5-9y72+24y=-5y-524y=-77y=-77/29 | | -4s=-6-6s | | 4(2x-3)=8x-13 | | (n-7.9)=2 | | -39=-3c-3 | | 2(3b–4)=8b–11 | | -2-n=12 | | 8+2u=u | | 124.50=20(x+4)+0.75x+3 | | -11x-75=-1 | | 5x+12=24+3x | | -2-n=21 | | 10w-8w=16 | | 5(5x)+20x+12x=228 | | 1x-8=3x+4 | | 13+n=-40 | | y8-15=2 | | 3x+8X=15 | | 3m^2+19m-14=0 | | h-2/3+10=22 | | 4(x+5)+2(7-x)=50 | | 12+b6=16 | | -37-3x=7(1-2x) | | 440/x+348=356 | | -15=3+n | | 5(5x)+20x+12=228 |